ln(x+1)-lnx+ln(x^2)=1

Solution for ln(x+1)-lnx+ln(x^2)=1 equation:

Simplifying
ln(x + 1) + -1lnx + ln(x2) = 1

Reorder the terms:
ln(1 + x) + -1lnx + ln(x2) = 1
(1 * ln + x * ln) + -1lnx + ln(x2) = 1
(1ln + lnx) + -1lnx + ln(x2) = 1

Multiply ln * x2
1ln + lnx + -1lnx + lnx2 = 1

Combine like terms: lnx + -1lnx = 0
1ln + 0 + lnx2 = 1
1ln + lnx2 = 1

Solving
1ln + lnx2 = 1

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Reorder the terms:
-1 + 1ln + lnx2 = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + 1ln + lnx2 = 0

The solution to this equation could not be determined.